Brand new - be gent...

Brand new - be gentle

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(@zeferby)
Reputable Member
Joined: 7 months ago
Posts: 356
2020-02-06 10:13 pm

Another analogy :

Drop a very big stone from 1m high = high intensity/big Amps

Drop a small stone from 100m high = high voltage/big Volts

Drop a very big stone from 100m high = don't stand under it ! ?

Eric

(@grepler)
Active Member
Joined: 2 months ago
Posts: 8
2020-02-10 3:18 pm

Electrical Pressure (voltage) = Intensity of Current (amps) x Resistance (ohms)
E = I x R
where voltage, ampere and ohms are the units of measure like inches are to Distance.

So the reciprocal of this (if I wanted to solve for I) would be I=E/R correct?

(@pugwash)
Prominent Member
Joined: 10 months ago
Posts: 970
2020-02-10 3:30 pm

@grepler

I think it was my dad who taught me to remember the formulas like this:

Women Are Virgins    Watts = Amps * Volts

Virgins Are Rare      Volts = Amps * Resistance

As simple as that! And I never forgot it, even after 50 more years!

SteveC - Topple Rudd Poltman

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(@casey)
Reputable Member
Joined: 10 months ago
Posts: 363
2020-02-10 6:07 pm
Posted by: @grepler
So the reciprocal of this (if I wanted to solve for I) would be I=E/R correct?

Yes.

The other important measure in a dc circuit is power measured in watts.

Power (watts) =   *  Intensity of Current (amps) * Electric Pressure (volts)

P = I * E

This post was modified 2 months ago 2 times by casey

(@casey)
Reputable Member
Joined: 10 months ago
Posts: 363
2020-02-10 9:23 pm

Although it is probably obvious and because I can no longer edit the post I thought I should correct the typo in the formula just in case.

Power (watts) =  Intensity of Current (amps) * Electric Pressure (volts)

What some people suggest may help is to use the diagram below and simply cover the value you are looking for with a finger and the remaining is the required calculation.

This post was modified 2 months ago by casey

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