Another analogy :

Drop a very big stone from 1m high = high intensity/big Amps

Drop a small stone from 100m high = high voltage/big Volts

Drop a very big stone from 100m high = don't stand under it ! ?

Eric

Electrical Pressure (voltage) = Intensity of Current (amps) x Resistance (ohms)

E = I x R

where voltage, ampere and ohms are the units of measure like inches are to Distance.

So the reciprocal of this (if I wanted to solve for I) would be I=E/R correct?

Yes.

The other important measure in a dc circuit is power measured in watts.

Power (watts) = * Intensity of Current (amps) * Electric Pressure (volts)

P = I * E

Although it is probably obvious and because I can no longer edit the post I thought I should correct the typo in the formula just in case.

Power (watts) = Intensity of Current (amps) * Electric Pressure (volts)

What some people suggest may help is to use the diagram below and simply cover the value you are looking for with a finger and the remaining is the required calculation.