Another analogy :
Drop a very big stone from 1m high = high intensity/big Amps
Drop a small stone from 100m high = high voltage/big Volts
Drop a very big stone from 100m high = don't stand under it ! ?
Eric
Electrical Pressure (voltage) = Intensity of Current (amps) x Resistance (ohms)
E = I x R
where voltage, ampere and ohms are the units of measure like inches are to Distance.
So the reciprocal of this (if I wanted to solve for I) would be I=E/R correct?
Yes.
The other important measure in a dc circuit is power measured in watts.
Power (watts) = * Intensity of Current (amps) * Electric Pressure (volts)
P = I * E
Although it is probably obvious and because I can no longer edit the post I thought I should correct the typo in the formula just in case.
Power (watts) = Intensity of Current (amps) * Electric Pressure (volts)
What some people suggest may help is to use the diagram below and simply cover the value you are looking for with a finger and the remaining is the required calculation.