As for the atoi() it  will  not. I was thinking that the odd characters would have some ascii value but no.

Thanks for your inputs.

That way you can go to the pointer address itself

-----

Anyways ....

You assigned an int pointer to a character pointer which is ok.

But now the char pointer is now pointing at an 8 bit value. 

If that value is below 32 that is a control character and is  a non-printable ascii value.

https://youtu.be/jdQaaFNpM_4

https://forum.arduino.cc/t/strings-pointers/657671

I think that your problem is that you are assuming that the '1025' is stored as a series of characters instead of the binary value that yo originally stored there. So the value stored at the location iValue is 10000000001 binary or 401 hex.

You must remember that the value stored in a computer depends on the type of value stored and you must extract and process it according to the form it was loaded. So here, the value 1025 its stored as a binary  value and you are trying to interpret the bytes at that location as a character string

Why do you think the output is wrong?

What do you think atoi does?

hint: look up the description of atoi.

On playing with pointers I get odd results that I do not understand. Perhaps you all can understand the problem. This is the code and attached are the results. Thanks for looking.

#define print Serial.print
#define printf Serial.println
void setup() 
{
  Serial.begin(9600);
}

void loop()
{
  int iValue = 1025; // .... .... 00000100 00000001 
  int *iPtr = &iValue; 
  char *cPtr;
  
  cPtr = (char*)iPtr;        //typecasting 

  print(" *iPtr ");      printf(*iPtr); // should be 1025 - okay
   
  print(" *cPtr ");      printf(*cPtr); // should be 1 at first byte;  got inverted L
  print(" *(cPtr+1) ");  printf(*(cPtr+1)); // should be 4 at second byte; got flipped L

  print(" atoi(*cPtr) ");      printf(atoi(*cPtr)); // should be ascii value of odd char 1
  print(" atoi(*(cPtr+1)) ");  printf(atoi(*(cPtr+1))); // should be ascii value ofaodd char 2
 
  delay(1000);

}